Question

How do you subtract `\frac { 3y - 1} { 3y + 1} - \frac { 2y - 5} { y - 3}`?

Answer 1

answer: `3y^2−23y`

Explanation:

multiply both fractions by `(3y+1)(y-3):`

`(3y-1)(y-3) - (2y-5)(3y+1)`

`= 3y^2-9y-y+3 - 6y^2+2y-15y-3`

collect like terms:
`-3y^2-23y (` `+-` #0) =-3y^2-23y #