# How do you subtract (x^2-8x+7)-(6x^2+7x-3)?

Feb 5, 2015

You need to remember that the $-$ is actually a $- 1$ in front of the second expression.

$\left({x}^{2} - 8 x + 7\right) - 1 \left(6 {x}^{2} + 7 x - 3\right)$

The first set of parentheses can drop since there is merely a 1 in front of them. You will need to distribute the $- 1$ to the second set of parentheses.

${x}^{2} - 8 x + 7 - 6 {x}^{2} - 7 x + 3$

Now you are ready to combine like terms. Remember that the sign in front of the term moves with the term.

${x}^{2} - 6 {x}^{2} - 8 x - 7 x + 7 + 3$

$- 5 {x}^{2} - 15 x + 10$