How do you use a sigma notation to write an equation for the series: 1/2+2/3+3/4+4/5+...+7/8?

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Answer 1 · 2018-03-06T09:49:24

#sum_(n=1)^7n/(n+1)#

we have

#1/2+2/3+3/4+4/5+...7/8#

the numerators go from #n=1, "to "n=7#

we notice also that the denominators are always one more than the numerator so the general term is of the form

#n/(n+1)#

putting the summation in

#sum_(n=1)^7n/(n+1)#