# How do you use Heron's formula to determine the area of a triangle with sides of that are 6, 4, and 4 units in length?

Feb 9, 2016

Area ≈ 7.94

#### Explanation:

This is a 2 step process

step 1 : calculate ( half of the perimeter (s) ) of the triangle

step 2 : calculate the area (A)

let a = 6 , b = 4 and c = 4

step 1 : s = $\frac{a + b + c}{2} = \frac{6 + 4 + 4}{2} = \frac{14}{2} = 7$

step 2 : A$= \sqrt{s \left(s - a\right) \left(s - b\right) \left(s - c\right)}$

$= \sqrt{7 \left(7 - 6\right) \left(7 - 4\right) \left(7 - 4\right)}$

 = sqrt(7 xx 1 xx 3 xx 3) = sqrt63 ≈ 7.94