Question

How do you use the amplitude and period to graph `y=cos(x°+45°)-1`?

Answer 1

Amplitude is `1` and period is `2pi`.

Explanation:

In a typical sine or cosine function `y=alphacos(betax+gamma)+delta`,

`alpha` denotes amplitude,

period is `(2pi)/beta` or `360^o/beta`

phase shift is given by `(-gamma)/beta`

and `delta` denotes vertical shift.

Hence in `cos(x^o+45^o) -1`

Amplitude is `1` and period is `2pi`.

graph{cos(x+pi/4) -1 [-10, 10, -5, 5]}