Question

How do you use the chain rule to differentiate `y=(6-2x)^3`?

Answer 1

`y' = -6(6-2x)^2`

Explanation:

`y = (6-2x)^3`

Use `(u^n)' = n u^(n-1) u'`

Let `u = 6-2x`, `u' = -2; n = 3`

`y' = 3(6-2x)^2 (-2) = -6(6-2x)^2`