Question

How do you use the chain rule to differentiate `y=8(x^4-x+1)^(3/4)`?

Answer 1

`dy/dx=6(x^4-x+1)^(-1/4) +(4x^3-1)`

Explanation:

Given -

`y=8(x^4-x+1)^(3/4)`
`dy/dx=[8*3/4(x^4-x+1)^((3/4)-1)]xxd/dx(x^4-x+1)`

`dy/dx=6(x^4-x+1)^(-1/4)(4x^3-1)`