# How do you use the Change of Base Formula and a calculator to evaluate the logarithm log_6 11?

${\log}_{6} \left(11\right) \approx 1.3382$
Change of base formula: ${\log}_{b} \left(N\right) = {\log}_{a} \frac{N}{\log} _ a \left(b\right)$
${\log}_{6} \left(11\right) = {\log}_{10} \frac{11}{\log} _ 10 \left(6\right) = \log \frac{11}{\log} 6 \approx 1.3382$ OR
${\log}_{6} \left(11\right) = {\log}_{e} \frac{11}{\log} _ e \left(6\right) = \ln \frac{11}{\ln} 6 \approx 1.3382$ [Ans]