How do you use the distributive property to find 5 x 89?

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Answer 1 · 2018-03-14T13:36:11

#445#

#"express 89 as "89=(90-1)#

#rArr5(90-1)#

#=450-5#

#=445#

Answer 2 · 2018-03-14T13:36:11

See a solution process below:

We can rewrite the number 89 as:

#89 = 80 + 9#

We then rewrite the expression in the problem as:

#5 xx (80 + 9)# or #5(80 + 9)#

Using the distributive property we can rewrite and evaluate the expression as:

#(5 xx 80) + (5 xx 9) =>#

#400 + 45 =>#

#445#