How do you use the distributive property to rewrite and evaluate #(4+6)11#?

1 Answer
Mar 31, 2017

Answer:

#(4+6)11 = 4*11+6*11 = 44+66 = 110#

Explanation:

The distributive property has two forms:

#a(b+c) = ab+ac" "# "left distributive"

#(a+b)c = ac+bc" "# "right distributive"

When dealing with arithmetic of ordinary numbers, where multiplication is commutative, these can be derived from one another, but in other contexts they both need to be stated.

In our example, we use right distributivity to find:

#(4+6)11 = 4*11+6*11#

Then evaluating:

#4*11+6*11 = 44+66 = 110#