How do you use the important points to sketch the graph of #y=(x-5)^(2)#?

1 Answer
Jul 21, 2018

#(5,0), (6,1), (7,4), (4,1), (3,4)#
graph{(x-5)^2 [-10, 10, -5, 5]}

Explanation:

First, start off with the important points of the parent function #y=x^2# which are #(0,0), (1,1), (2,4), (-1,1), (-2,4)#

graph{x^2 [-10, 10, -5, 5]}

From the #x-5# in this equation, we know that each #x# coordinate of each important point shifts right #5# units, so we can add #5# to each #x# coordinate on the important points of the parent function, giving us the new coordinates of

#(5,0), (6,1), (7,4), (4,1), (3,4)#

graph{(x-5)^2 [-10, 10, -5, 5]}