Question

How do you use the law of sines to solve the triangle given A = 75.1°, B = 37.9°, b = 13.3?

Answer 1

Use the trig identity: a/sin A = b/sin B

`a = (b.sin A)/sin B = (13.3 (0.966))/0.61 = 21.06`

C = 180 - A - B = 180 - 75.1 - 37.9 = 67.