How do you use the quadratic formula to solve #5x^3+3x-2=0#?

1 Answer
George C.
Aug 20, 2016

#x=2/5# or #x=-1#

Explanation:

#5x^2+3x-2=0# is in the form #ax^2+bx+c=0# with #a=5#, #b=3# and #c=-2#.

So using the quadratic formula we have:

#x = (-b+-sqrt(b^2-4ac))/(2a)#

#= (-3+-sqrt(3^2-4(5)(-2)))/(2*5)#

#= (-3+-sqrt(4+40))/10#

#= (-3+-sqrt(49))/10#

#= (-3+-7)/10#

That is #x=2/5# or #x=-1#

Related questions
Impact of this question
375 views around the world
You can reuse this answer
Creative Commons License