How do you use the quadratic formula to solve #-x^2+1=-6x^2-x#?
Sub in coefficients from standard form into QF. Solve for
So first off, we have to transform the equation to standard form.
To do this, we have to bring all the terms to one side and equate the equation to 0.
#f(x)=-x^2 + 6x^2+x+1=0#
Now we add like terms.
Once we have our equation in standard form, we use the quadratic formula:
We sub in the
I stopped here, because under the radical, we have a negative number. It's impossible to root a negative number - it becomes undefined.
The value under the radical indicates the number of zeros the equation has. A positive number greater than
Therefore, the solution to this equation
Hope this helps :)