# How do you use the quadratic formula to solve #-x^2+1=-6x^2-x#?

##### 1 Answer

Sub in coefficients from standard form into QF. Solve for

#### Explanation:

So first off, we have to transform the equation to standard form.

#f(x)=-x^2+1=-6x^2-x#

To do this, we have to bring all the terms to one side and equate the equation to 0.

#f(x)=-x^2 + 6x^2+x+1=0#

Now we add like terms.

#f(x)=5x^2+x+1=0#

Once we have our equation in standard form, we use the quadratic formula:

We sub in the

#x=\frac{-b\pm\sqrt{b^2-4ac\ }}{2a}#

#x=\frac{-(1)\pm\sqrt{(1)^2-4(5)(1)\ }}{2(5)}#

#x=\frac{-1\pm\sqrt{-19\ }}{10}#

I stopped here, because under the radical, we have a negative number. It's impossible to root a negative number - it becomes undefined.

The value under the radical indicates the number of zeros the equation has. A positive number greater than

Therefore, the solution to this equation

Hope this helps :)