# How do you use the Squeeze Theorem to find #lim(x-1)sin(pi/x-1) # as x approaches one?

##### 2 Answers

#### Explanation:

Firstly, we don't need the squeeze theorem because the function is continuous at values close to

If we have

Multiplying both sides by

Since

The squeeze theorem tells us that

#### Explanation:

**Limit from the right is 0**

For

So

**Limit from the left is 0**

For

So

**Therefore,**