How do you write 2x^2 - 3 = -6x - 2 in standard form?

Apr 15, 2016

$2 {x}^{2} + 6 x - 1 = 0$

Explanation:

Standard form of a quadratic equation looks like this:
$a {x}^{2} + b x + c = 0$

So basically, we need one side of the equation to be $0$.

$2 {x}^{2} - 3 = - 6 x - 2$

add everything to the left side
$2 {x}^{2} - 3 + 6 x + 2 = 0$

simplify
$2 {x}^{2} + 6 x - 1 = 0$

usually you want $a$ (which is $2$ in this case) to be positive, and it is so we are done.