# How do you write (2x + 3)(3x + 4)  in standard form?

Sep 13, 2017

See a solution process below:

#### Explanation:

To put this expression in standard form we must multiply the two terms in parenthesis. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$\left(\textcolor{red}{2 x} + \textcolor{red}{3}\right) \left(\textcolor{b l u e}{3 x} + \textcolor{b l u e}{4}\right)$ becomes:

$\left(\textcolor{red}{2 x} \times \textcolor{b l u e}{3 x}\right) + \left(\textcolor{red}{2 x} \times \textcolor{b l u e}{4}\right) + \left(\textcolor{red}{3} \times \textcolor{b l u e}{3 x}\right) + \left(\textcolor{red}{3} \times \textcolor{b l u e}{4}\right)$

$6 {x}^{2} + 8 x + 9 x + 12$

We can now combine like terms:

$6 {x}^{2} + \left(8 + 9\right) x + 12$

$6 {x}^{2} + 17 x + 12$