# How do you write 33^(7/8) exponential expression in radical form?

${\sqrt[8]{33}}^{7}$
In the exponential, you can view the denominator as your root, and your numerator will stay exponential. for example, if your equation is ${x}^{\frac{1}{2}}$, that is the same as saying ${\sqrt{x}}^{1}$. So when our denominator is 8 in our exponential, we take the root of 8, while the numerator stays as an exponential, giving us ${\sqrt[8]{33}}^{7}$