# How do you write (-3x-1)(x+1) in standard form?

Mar 13, 2016

$- 3 {x}^{2} - 4 x - 1$

#### Explanation:

multiply out the brackets. Each term in the 2nd bracket must be multiplied by each term in the 1st. To ensure this happens set out as follows :

$- 3 x \left(x + 1\right) - 1 \left(x + 1\right)$

$= - 3 {x}^{2} - 3 x - x - 1 = - 3 {x}^{2} - 4 x - 1$

Standard form is writing the expression , starting with the term that has the highest power of the variable followed by terms with decreasing powers until the last term , usually a constant.

${a}_{n} {x}^{n} + {a}_{n - 1} {x}^{n - 1} + {a}_{n - 2} {x}^{n - 2} + \ldots \ldots + {a}_{0} {x}^{0}$

hence : $- 3 {x}^{2} - 4 x - 1 \text{ is in standard form }$