How do you write # 3x^2 = 5 - 2x# in standard form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Tony B May 2, 2016 #y=3x^2+2x-5# Explanation: Subtract 5 from both sides #3x^2-5=0-2x# Add #2x# to both sides #3x^2+2x-5=0# Equate to #y# #y=3x^2+2x-5# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 15031 views around the world You can reuse this answer Creative Commons License