# How do you write 4^(x+1) = 32 in log form?

Aug 25, 2016

${4}^{x + 1} = 32 \text{ " hArr " } {\log}_{4} 32 = x + 1$

#### Explanation:

log form and index form are interchangeable:

${\log}_{a} b = c \text{ " hArr" } {a}^{c} = b$

"The base stays the base and the other two swop around"

${4}^{x + 1} = 32 \text{ " hArr " } {\log}_{4} 32 = x + 1$