# How do you write 4x^2-24x+27 in the form of a(x-b)^2+c?

Sep 8, 2017

$= 4 {\left(x - 3\right)}^{2} - 9$

#### Explanation:

$4 {x}^{2} - 24 x + 27 = 4 \left({x}^{2} - 6 x\right) + 27$

$= 4 {\left(x - \frac{6}{2}\right)}^{2} - 4 {\left(\frac{6}{2}\right)}^{2} + 27$

$= 4 {\left(x - 3\right)}^{2} - 4 {\left(3\right)}^{2} + 27$

$= 4 {\left(x - 3\right)}^{2} - 36 + 27$

$= 4 {\left(x - 3\right)}^{2} - 9$