# How do you write #5n^2+19n-68=-2# into vertex form?

##### 1 Answer

May 14, 2015

to be written in the form:

Temporarily extract the constant from the working left side

#5n^2+19n = 66#

Extract the

#5(n^2+19/5n) = 66#

Complete the square

#5(n^2+19/5n+(19/10)^2) = 66 + 5(19/10)^2#

#5(n+19/10)^2 = 66 + 361/20 = 1681/20#

Move the constant back to the left side to complete the vertex form:

#5(n+19/10)^2 - 1681/20 = 0#

or

#5(n-(-19/10))^2 +(- 1681/20) = 0#