How do you write 5x-4y=8 in slope intercept form?

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Answer 1 · 2018-04-07T14:18:00

#-y = -5/4x + 2#

#y = mx + b#

#"m = slope"#
#"b = y-intercept"#

So we'll just rearrange your current equation to be in slope-intercept form.

#5x-4y=8#

#-4y = - 5x + 8 #

#-y = -5/4x + 2#

Now I'm going to multiply the whole equation by #-1#, because I don't want #y# to be negative. This will change the sign of all the parts.

#y = 5/4x - 2#

graph{y = 5/4x - 2 [-12.66, 12.65, -6.33, 6.33]}