# How do you write -8-(3+2i)-(9-4i) in standard form?

Jan 6, 2018

$- 20 + 2 i$

#### Explanation:

Standard form for complex numbers is $a + b i$, where $a$ and $b$ are integers. To get this, we just have to combine all the terms with $i$ and all the terms without $i$.

Simplifying the expression:

$- 8 - \left(3 + 2 i\right) - \left(9 - 4 i\right)$

$= - 8 - 3 - 2 i - 9 + 4 i$

Regrouping the terms:

$= \left(- 8 - 3 - 9\right) + \left(- 2 i + 4 i\right)$

$= - 20 + 2 i$