# How do you write (8m^2-3)(8m^2+3) in standard form?

$\left(8 {m}^{2} - 3\right) \left(8 {m}^{2} + 3\right)$
$= 64 {m}^{4} + 24 {m}^{2} - 24 {m}^{2} - 9$
=$64 {m}^{4} - 9$