How do you write a polynomial equation of least degree given the roots 6, 2i, -2i, i, -i? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Sasha P. Apr 23, 2017 #z^5-6z^4+5z^3-30z^2+4z-24=0# Explanation: #(z-6)(z-2i)(z-(-2i))(z-i)(z-(-i))=0# #(z-6)(z-2i)(z+2i)(z-i)(z+i)=0# #(z-6)(z^2-2zi+2zi-4i^2)(z^2-zi+zi-i^2)=0# #(z-6)(z^2+4)(z^2+1)=0# #(z-6)(z^4+4z^2+z^2+4)=0# #(z-6)(z^4+5z^2+4)=0# #z^5-6z^4+5z^3-30z^2+4z-24=0# Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 1550 views around the world You can reuse this answer Creative Commons License