How do you write a polynomial in standard form given the zeros 5 and 1+2i? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Cem Sentin Mar 26, 2018 #x^3-7x^2+15x-25# Explanation: If #1+2i# is root of a polynomial, #1-2i# also the root of it. Hence, #P(x)=(x-5)(x-1+2i)(x-1-2i)# =#(x-5)(x^2-2x+5)# =#x^3-7x^2+15x-25# Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 3136 views around the world You can reuse this answer Creative Commons License