Question

How do you write a quadratic equation with vertex; ( 1,0 ); point: ( -1,4 )?

Answer 1

y = (x - 1)^2

Explanation:

Vertex form of this function:
`y = a(x - 1)^2 + 0`.
Find a by writing that the parabola passes at point (-1, 4):
`4 = a(-2)^2 = 4a` --> a = 1
This function has as standard form:
`y = (x - 1)^2`