# How do you write an equation for these points (4,-2); m=1/4?

##### 1 Answer
Nov 4, 2016

$y = \frac{1}{4} x - 3$

#### Explanation:

The equation of a line in $\textcolor{b l u e}{\text{point-slope form}}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{y - {y}_{1} = m \left(x - {x}_{1}\right)} \textcolor{w h i t e}{\frac{2}{2}} |}}}$
where m represents the slope and $\left({x}_{1} , {y}_{1}\right) \text{ a point on the line}$

here $m = \frac{1}{4} \text{ and } \left({x}_{1} , {y}_{1}\right) = \left(4 , - 2\right)$

substitute these values into the equation.

$y - \left(- 2\right) = \frac{1}{4} \left(x - 4\right)$

$\Rightarrow y + 2 = \frac{1}{4} \left(x - 4\right) \leftarrow \text{ point-slope form}$

distribute the bracket and collect like terms.

$y + 2 = \frac{1}{4} x - 1$

$\Rightarrow y = \frac{1}{4} x - 3 \leftarrow \text{ slope-intercept form}$