How do you write an equation in form of the line that passes through the points (4, 2) and (1,-7)?

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Answer 1 · 2017-10-19T11:14:48

The equation of the line in standard form is #3x-y=10 #

The slope of the line passing through #(4,2) and (1,-7)# is #m= (y_2-y_1)/(x_2-x_1)= (-7-2)/(1-4)=(-9)/-3 =3#

Let the equation of the line in slope-intercept form be

#y=mx+c or y=3x+c#.The point (4,2) will satisfy the

equation . So, # 2= 3*4+c :. c= -10#

Hence the equation of the line in slope-intercept form is

#y= 3x-10#. The equation of the line in standard form is

#3x-y=10 # {Ans]