How do you write an equation in slope intercept form given (5,7), (-3,11)?

1 Answer
Nov 14, 2016

Answer:

#y=-12x+9 1/2#

Explanation:

Step 1: Write in slope-point form

#color(white)("XXX")#Step 1a: Determine the slope
#color(white)("XXX")color(green)m=(Deltay)/(Deltax)=(11-7)/(-3-5)=4/(-8)=color(green)(-1/2)#

#color(white)("XXX")#Step 1b: Use one of the given points to write in slope-point form:
#color(white)("XXX")y-7=-1/2(x-5)#

Step 2: Convert into slope-intercept form:
#color(white)("XXX")#Note the slope-intercept form is
#color(white)("XXXXXX")y=color(green)(m)x+color(blue)b#
#color(white)("XXX")#for a line with slope #color(green)(m)# and y-intercept #color(blue)(b)#

#color(white)("XXX")y=color(green)(-1/2)x+5/2+7#

#color(white)("XXX")y=color(green)(-1/2)x+color(blue)(19/2)#

Here is the graph of #y=-1/2x+19/2# with the given points for verification purposes:
enter image source here