How do you write an equation in slope intercept form given 5x+8y=96?

1 Answer
Jul 14, 2016

#y = -5/8x + 12#

Explanation:

Slope intercept form: #y=mx+b# where #m# is the slope and #b# is the y intercept.

#5x + 8y = 96#

Let's rewrite this equation in slope intercept form. First get the #y# variable term by itself.

#8y = 96 - 5x#

Now divide out the #8#.

#y = 12 - 5/8x#

Rearrange the terms on the right side of the equal sign to match the slope intercept equation from above.

#y = -5/8x + 12#

If you were to graph this line it would look like: graph{-5/8x + 12 [-10.04, 9.96, 7.46, 17.88]}