First, we need to determine the slope of the line. The slope can be found by using the formula: #m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))#

Where #m# is the slope and (#color(blue)(x_1, y_1)#) and (#color(red)(x_2, y_2)#) are the two points on the line.

Substituting the values from the points in the problem gives:

#m = (color(red)(-1) - color(blue)(0))/(color(red)(5) - color(blue)(1)) = -1/4#

Next we can use the point-slope formula to write an equation for the line. The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #(color(red)(x_1, y_1))# is a point the line passes through. Substituting the slope we calculated and the values from the second point in the problem gives:

#(y - color(red)(-1)) = color(blue)(-1/4)(x - color(red)(5))#

#(y + color(red)(1)) = color(blue)(-1/4)(x - color(red)(5))#

We can also substitute the slope we calculated and the values from the first point in the problem giving:

#(y - color(red)(0)) = color(blue)(-1/4)(x - color(red)(1))#

We can solve this equation for #y# to write an equation in slope intercept form. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

#y = (color(blue)(-1/4) xx x) + (color(blue)(-1/4) xx -color(red)(1))#

#y = color(red)(-1/4)x + color(blue)(1/4)#