How do you write an equation of a line given slope 5/2 and passes through (4,-1)?

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Answer 1 · 2016-02-18T17:17:08

#y = 5/2x - 11#

To determine the equation of the line we can use the point slope formula and plug in the values given in the question.

#(y - y_1) = m(x - x_1)#

#m = 5/2#
#x_1 = 4#
#y_1=-1#

#(y - (-1)) = 5/2#(x - 4)#

#y +1 = 5/2x - 10#

#y +1-1 = 5/2x - 10-1#

#y = 5/2x - 11#