How do you write an equation of a line passing through (2, -2), perpendicular to #y = –x + 3#?

1 Answer
Dec 6, 2017

Answer:

#y=x-4#

Explanation:

#"given a line with slope m then the slope of a line"#
#"perpendicular to it is"#

#•color(white)(x)m_(color(red)"perpendicular")=-1/m#

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#y=-x+3" is in this form"#

#"with "m=-1#

#rArrm_(color(red)"perpendicular")=-1/(-1)=1#

#rArry=x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute "(2,-2)" into the partial equation"#

#-2=2+brArrb=-4#

#rArry=x-4larrcolor(red)"in slope-intercept form"#