How do you write an equation of the line that passes through the given points (-7,0), (4,11)?

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Answer 1 · 2016-11-19T07:29:24

#y= x+7#

The equation of a line can be given as #y = mx +c#

As you have 2 points, you can find the slope:

#m = (y_2-y_1)/(x_2-x_1) = (11-0)/(4- (-7)) = 11/11#

#m = 1#

Now to find a value for #c#, substitute #m# and one of the points #(x,y)# into #y= mx+c#

#m = 1 and (x,y) = (-7,0)#

#0= (1)(-7) +c#

#7=c#

The equation is #y= x+7#