How do you write an equation of the line that passes through the points (4,3) and (-6,-3)?

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Answer 1 · 2018-04-27T11:42:14

Equation of the line in slope-intercept form is
#y= 3/5 x +3/5 #

The slope of the line passing through #(4,3) and (-6,-3)# is

#m= (y_2-y_1)/(x_2-x_1)= (-3-3)/(-6-4)=(-6)/-10=3/5#

Let the equation of the line in slope-intercept form be

#y=m x+c :. y= 3/5 x +c # The point (4,3) will satisfy

the equation .#:. 3= 3/5*4+c or c= 3-12/5= 3/5#

Hence equation of the line in slope-intercept form is

#y= 3/5 x +3/5 # [Ans]