How do you write an exponential function whose graph passes through (0,3) and (1,15)?

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Gió Share
Jan 10, 2017

Answer:

I got #y=3e^(xln(5))#

Explanation:

I would try to use the coordinates of your points:
enter image source here

Our function maight be:
#y=3e^(xln(5))#
Or using #ln(5)=1.61#
#y=3e^(1.61x)#

Graphically:
graph{3e^(1.61x) [-9.84, 10.16, -9.32, 0.68]}

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