How do you write f(x) = 4x^2 +28x +45 in vertex form?

$f \left(x\right) = 4 {\left(x + \frac{7}{2}\right)}^{2} - 4$
$f \left(x\right) = 4 {x}^{2} + 28 x + 45 \mathmr{and} f \left(x\right) = 4 \left({x}^{2} + 7 x + {\left(\frac{7}{2}\right)}^{2}\right) - 49 + 45 \mathmr{and} f \left(x\right) = 4 {\left(x + \frac{7}{2}\right)}^{2} - 4$ Here vertex is at $\left(- \frac{7}{2} , - 4\right)$ graph{(x+7/2)^2-4 [-10, 10, -5, 5]} [ans]