# How do you write #log_(1/25)5=-1/2# in exponential form?

##### 2 Answers

Mar 21, 2018

#### Explanation:

Hence

Mar 21, 2018

#### Explanation:

#"using the "color(blue)"law of logarithms"#

#â€¢color(white)(x)log_b x=nhArrx=b^n#

#"here "x=5,b=1/25" and "n=-1/2#

#rArrlog_(1/25)5=-1/2hArr5=(1/25)^(-1/2)#