How do you write #Log_2 1024 = 10 # in exponential form?

Question

8514 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-31T13:37:29

#2^10=1024#

#log_a b=n# in exponential form is written as #a^n=b#.

Hence, #log_2 1024=10# can be written in exponential form as

#2^10=1024#

Answer 2 · 2016-08-31T14:42:20

#2^10 = 1024#

So #log_2 1024 = 10#

log form and exponential (or index) form are interchangeable.

Simply remember:

"The base stays the base, and the other two swop around"

#log_color(red)(a) color(blue)(b)= color(lime)(c) hArr color(red)(a)^color(lime)(c) = color(blue)(b)#

What is #log_2 1024 # ?

In log form the question being asked is ...

"What index/power of 2 will give 1024?"

It is a real advantage to know all the powers up to 1000.

#2^10 = 1024#

So #log_2 1024 = 10#