How do you write the answer of #0.2(3times10^2)# in scientific notation?

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Answer 1 · 2017-02-26T08:42:50

#6xx10#

#0.2(3xx10^2)#

#= 0.2 xx3xx10^2" "larr# multiply the numbers

#=0.6 xx 10^2#

But in standard form there must be one non-zero digit at the front.
(Dividing by 10 reduces the index by 1)

#0.6 xx 10^2 = 6 xx 10^1 = 6xx10#

Answer 2 · 2017-02-26T08:43:17

#=6xx10^1#

Change all the numbers to standard index form, then do the calculations.

#0.2(3xx10^2)=(2xx10^(-1))xx(3xx10^2)#

#=(2xx3)xx10^(-1+2)#

#=6xx10^1#