# How do you write the balanced equation for the hydration of CuSO_4?

Nov 15, 2016

$\text{CuSO"_4"(s)" + "5H"_2"O(l)" → "CuSO"_4·"5H"_2"O(s)}$

#### Explanation:

The formula for the hydrated ${\text{CuSO}}_{4}$ is $\text{CuSO"_4·"5H"_2"O}$.

The unbalanced equation is

$\text{CuSO"_4"(s)" + "H"_2"O(l)" → "CuSO"_4·"5H"_2"O(s)}$

To balance it, put a 5 in front of $\text{H"_2"O}$.

This gives the balanced equation

$\text{CuSO"_4"(s)" + "5H"_2"O(l)" → "CuSO"_4·"5H"_2"O(s)}$