Question

How do you write the balanced equation for the hydration of `CuSO_4`?

Answer 1

`"CuSO"_4"(s)" + "5H"_2"O(l)" → "CuSO"_4·"5H"_2"O(s)"`

Explanation:

The formula for the hydrated `"CuSO"_4` is `"CuSO"_4·"5H"_2"O"`.

The unbalanced equation is

`"CuSO"_4"(s)" + "H"_2"O(l)" → "CuSO"_4·"5H"_2"O(s)"`

To balance it, put a 5 in front of `"H"_2"O"`.

This gives the balanced equation

`"CuSO"_4"(s)" + "5H"_2"O(l)" → "CuSO"_4·"5H"_2"O(s)"`