# How do you write the equation in point slope form given slope -1/5 ,ordered pair (5, -1)?

$y + 1 = - \frac{1}{5} \left(x - 5\right)$
The structure for a point-slope equation is $y - y 1 = m \left(x - x 1\right)$ where m is slope and the subscript 1's refer to the coordinates in the given ordered pair. Since both the coordinates and the slope of this line are given, all you need to do is substitute the values into the formula.
y1 would be the given y value in the ordered pair, which is -1. The same is done for the x1 value, which is 5. The slope is -1/5. By substitution, the resulting equation is $y - \left(- 1\right) = - \frac{1}{5} \left(x - \left(5\right)\right)$. We then simplify the signs, which means the double negatives become a positive, so the answer comes to $y + 1 = - \frac{1}{5} \left(x - 5\right)$.