Question

How do you write the equation in slope intercept form given (1,-3) with x-intercept = -1?

Answer 1

`y = mx + b` where `y = -3/2x -1 1/2`

Explanation:

Explanation

Explanation:

In `y = mx + b` The slope intercept form
m = the slope think m = mountain slope
b = the y-intercept think b = beginning starting point.
m ; the slope = the change in y divided by the change in x

`(y_2 - y_1)/(x_2 - x_1)` = m

Substitute -3 for `y_2` and 0 for `y_1` ( y is zero at the x intercept)
Substitute 1 for `x_2` and -1 for `x_1` ( -1 is the x intercept)

`( -3 - 0) / { 1 - ( -1 )` = m

m = `-3/( +2)`

Now, to find the y-intercept remember `x=0` at the y-intercept.
So one point is ( 0, b) and a second point is ( 1,-3)

`(b - ( -3))/( 0 - 1 ) = -3/2`

`(b+3)/(-1) = (-3)/2`

multiplying both sides by -1 gives

`b + 3 = 3/2`
subtracting -3 from both sides gives

`b = 3/2 - 3`

`b = - 3/2`