# How do you write the equation in slope intercept form given #2x + 3y = 12#?

##### 1 Answer

#### Explanation:

The slope-intercept form of an equation looks like the following:

** #y = mx +b#** , where

So, to get the equation from

**1.) Get the #y# term all by itself.**

**2.) Get the variable #y# so that there are no coefficients. This means we need to divide the whole thing by 3 to get y by itself, completely.**

**3.) Now rearrange the terms in the right side of the equall sign to get the form of #mx + b#.**

*Summary:
We first got the #y# term by itself (on one side of the equation). Then, we got ride of the coefficient (number before the #y# variable) by dividing it out. After that, we rearranged the terms #4# and #-2/3x# so that it forms #-2/3x + 4#. The final equation is #y = -2/3x + b#. And your equation is in the form #y = mx + b#!*