# How do you write the equation in slope intercept form given x-3y=6?

Apr 8, 2017

$y = \frac{1}{3} x - 2$

#### Explanation:

Given: $x - 3 y = 6$

Put in slope-intercept form $y = m x + b$:

Add $3 y$ to both sides of the equation to make it positive:

$x - 3 y + 3 y = 6 + 3 y$
$x = 6 + 3 y$

Subtract $6$ from both sides of the equation:

$x - 6 = 6 - 6 + 3 y$
$x - 6 = 3 y$

Divide both sides of the equation by $3$:

$\frac{x}{3} - \frac{6}{3} = \frac{3 y}{3}$
$\frac{1}{3} x - 2 = y$

So $y = \frac{1}{3} x - 2$