How do you write the equation in slope intercept form passing through #(7,11), (5,1)#?

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Answer 1 · 2018-03-22T11:30:09

The equation of line in slope intercept form is #y= 5x-24 #

The slope of the line passing through #(7,11) and (5,1)# is

#m= (y_2-y_1)/(x_2-x_1)= (1-11)/(5-7)=(-10)/-2=5#

Let the equation of line in slope intercept form be

#y=mx+c or y=5x+c#. The point #(7,11)# will satisfy the

equation, #:. 11= 5*7+c or c= 11-35= -24#

Hence the equation of line in slope intercept form is

#y= 5x-24 # [Ans]