Question

How do you write the equation of a line given (-3,2) (3,6)?

Answer 1

`y = 2/3x + 4`

Explanation:

`(-3,2) and (3,6)`
`y = mx + b`

For `m`, which is slope

`(y_2-y_1)/(x_2-x_1) = m " (slope)"`

so

`(6-2)/(3 - (-3)) = 4/6 = 2/3 = m`

`y = 2/3x + b`

for b - use one of the points for `(x,y)`

`y=2/3x + b`
`6= 2/3(3) + b`
`6= 2 + b`

`4=b`

Now we have `m and b`